ELF MIPS basic crackme

Root-me challenge: Find the validation password.

  1. Decompile the binary in, for example, Ghidra.

  2. Analysis

  • There is no check on the length of the input

  • There is a loop which checks that at indexes 8 - 16 there is an i

  1. Check the stack.

  2. Find the other characters.

  3. The password is 19 characters long.